sankara.deva2016@gmail.com
Bharat sreeram, Ventech It Solutions
-----------------------------------------------------------
ls()
--- list of of r objects.
rm("x")
-- removes object
-----------------------------------------
a <- 100
a = 100
b = 200
c = a + b
d = a^3
e = a**2
name = "Giri"
a%%2 ---> remainder.
----------------------------------
> x = c (10,20,30,40,23,45,67,90)
> x[1] # first element
> length(x) # number of elements
> x[length(x)] # last element
> x[1:3] # first 3 elements
> x[4:length(x)] # 4th onwards
> x[9]=100 # adding 9 th element
> x[length(x)+1]=150 # adding element to last.
--------------------------------
> x
[1] 10 20 30 40 23 45 67 90 100 150
> y = x + 10
> y
[1] 20 30 40 50 33 55 77 100 110 160
>
z = c(1,2,3,4,5)
u = x + z
# element to element arithmetic operation will happen.
# if number of elements are different.
iterations will happen till all elements of
big vector is completed.
> sum(x)
[1] 575
> mean(x)
[1] 57.5
> length(x)
[1] 10
> max(x)
[1] 150
> min(x)
[1] 10
> var(x)
[1] 1953.389
> sd(x)
[1] 44.19716
>
-------------------------------------
gm = function(x){
v = 1
for (i in x){
v = v * i
}
n = length(x)
v^(1/n)
}
# last expression will be returned.
------------------------------------
hm = function(x) {
xx = 1/x
sxx = sum(xx)
n = length(x)
n/sxx
}
--------------------------------
# function for variance of population
vpop = function(x){
xbar = mean(x)
dev = x - xbar
sumdsq = sum( dev^2)
n = length(x)
sumdsq/n
}
# function for standard deviation of Population.
sdpop = function(x) {
sqrt(vpop(x))
}
--------------
a = 1:10
# generates auto sequence number,
incremented by 1.
b = 10:1
c = seq(10,100,5)
d = seq(100,10,-5)
-----------------------------------------
----------------------------
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